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5s^2-34s-7=0
a = 5; b = -34; c = -7;
Δ = b2-4ac
Δ = -342-4·5·(-7)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-36}{2*5}=\frac{-2}{10} =-1/5 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+36}{2*5}=\frac{70}{10} =7 $
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